DIRAC'S THEOREM - PROOF BY MATHEMATICAL INDUCTION

A proof by mathematical induction. Dedicated to my IB students of TCSH
Thanks to my IB students at TCSH, 

This proof is dedicated to all of you, an inspiration that comes from our math lessons together. 
I have looked into some books and internet sources and so far the proof uses the approach of a supposition of a longest path.

I welcome you all to study the proof by mathematical induction given here and tell me if I overlooked something. 

This is one way how you can do a math exploration.

Please click here for the proof.

SMK SEAFIELD MATH TALK 2014

MATHEMATICS - SELECTED STPM QUESTIONS FOR REVISION

SOLUTIONS

BE LUCKY


I express sincere thanks for the opportunity, Students! Your attention, cooperation, willingness to learn and good attendance gave a very good impression. Salute to your school! I wish you all great success in your exam. Special thanks also to Pn. Baizura and Pn. Chin for the support, both your presence throughout gave me added inspiration and showed how much you care for your students to do well. Congratulations SMK SEAFIELD. 

https://drive.google.com/file/d/0B3NUi_7xrhYgY2M0Qmw4VURJY2c/edit?usp=sharing

STPM FURTHER MATHEMATICS PAPER 2 - QUESTIONS & SOLUTIONS

My best wishes go to all taking this paper in May 2014.

This question paper is obtained from the specimen given together with the 2012 syllabus and exam format published by Majlis Peperiksaan Malaysia

https://drive.google.com/file/d/0B3NUi_7xrhYgY2M0Qmw4VURJY2c/edit?usp=sharing

CEVA'S & MENELAUS THEOREMS

Ceva's & Menelaus Theorem
https://drive.google.com/file/d/0B3NUi_7xrhYgdFFGTkpuVGFOYkE/edit?usp=sharing

A proof of CEVA'S & MENELAUS'S theorems without using triangles.
Both proofs use one property where fractions are equal as given below.
(a/p) = (b/q) = (c/r) = ... = (a + b + c+ ...)/(p + q + r + ...)